Method
Hydraulic power is P = ρgQH. The page divides by pump efficiency for shaft power, then by motor efficiency for electrical input. Annual energy is electrical input multiplied by the operating hours you enter.
Worked example
Water at 998 kg/m³, 50 m³/h and 30 m head needs about 4.08 kW hydraulic power; with 75% pump and 90% motor efficiency, electrical input is about 6.05 kW. At 4,000 annual operating hours, that is approximately 24.2 MWh/year before any variable-duty or tariff effects.
Important limits
Total dynamic head must represent the actual system at the selected flow. The annual estimate assumes a constant duty point and a single energy price. Select equipment from the manufacturer curve and separately verify NPSH, operating range, compatibility, drive losses, demand charges and margins.
Reference
U.S. Department of Energy: pumping-system assessment
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Frequently asked questions
What pump power equation does this calculator use?
Hydraulic power is P = ρgQH. The calculator divides it by pump efficiency for shaft power and by motor efficiency for electrical input.
What should total dynamic head include?
Use the total head at the stated flow: applicable static lift, pressure requirements and friction or fitting losses. Establish it from the actual system rather than treating it as a pump selection result.
How is annual pump energy estimated?
Electrical input power is multiplied by the annual operating hours you enter. The cost result then multiplies that energy by your entered electricity price, in your own currency unit.